# How do you graph using the intercepts for #5x+7y=77#?

##### 1 Answer

Nov 3, 2015

Plot the points for the x and y intercepts then draw a line through those points.

#### Explanation:

Given the equation

The x-intercept is the value of

The y-intercept is the value of

So the intercept points are at

If you plot these two points and draw a straight line through them, your graph should look something like:

graph{((x-15.4)^2 +y^2-0.1)(x^2+(y-11)^2-0.1)(5x+7y-77)=0 [-6.41, 25.63, -3.47, 12.55]}